Solution 1 - Track Sign

Return 0 if any element is 0; otherwise flip sign for each negative.

TimeComplexity: O(n)

SpaceComplexity: O(1)

""" 1822.1 - Sign of the Product of an Array - Solution 1 - Track Sign """

from typing import List

class Solution:
    def arraySign(self, nums: List[int]) -> int:
        sign = 1
        for x in nums:
            if x == 0:
                return 0
            if x < 0:
                sign *= -1
        return sign

1822 - Sign of the Product of an Array

Solution 1 - Track Sign